交叉字符串

来源：互联网发布：女生去夜店知乎编辑：程序博客网时间：2024/05/16 08:44

给出三个字符串:s1、s2、s3，判断s3是否由s1和s2交叉构成。

public boolean isInterleave(String s1, String s2, String s3) {        if (s1.length() + s2.length() != s3.length()) {            return false;        }                boolean [][] interleaved = new boolean[s1.length() + 1][s2.length() + 1];        interleaved[0][0] = true;                for (int i = 1; i <= s1.length(); i++) {            if(s3.charAt(i - 1) == s1.charAt(i - 1) && interleaved[i - 1][0])                interleaved[i][0] = true;        }                for (int j = 1; j <= s2.length(); j++) {            if(s3.charAt(j - 1) == s2.charAt(j - 1) && interleaved[0][j - 1])                interleaved[0][j] = true;        }                for (int i = 1; i <= s1.length(); i++) {            for (int j = 1; j <= s2.length(); j++) {                if(((s3.charAt(i + j - 1) == s1.charAt(i - 1) && interleaved[i - 1][j]))                    || ((s3.charAt(i + j - 1)) == s2.charAt(j - 1) && interleaved[i][j - 1]))                interleaved[i][j] = true;            }        }                return interleaved[s1.length()][s2.length()];    }}

阅读全文

0 0