HDU 1452 Happy 2004

题目链接 : HDU1452

Happy 2004

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 766    Accepted Submission(s): 535

Problem Description

Consider a positive integer X,and let S be the sum of all positive integer divisors of 2004^X. Your job is to determine S modulo 29 (the rest of the division of S by 29).

Take X = 1 for an example. The positive integer divisors of 2004^1 are 1, 2, 3, 4, 6, 12, 167, 334, 501, 668, 1002 and 2004. Therefore S = 4704 and S modulo 29 is equal to 6.

 

 

Input

The input consists of several test cases. Each test case contains a line with the integer X (1 <= X <= 10000000).

A test case of X = 0 indicates the end of input, and should not be processed.

 

 

Output

For each test case, in a separate line, please output the result of S modulo 29.

 

 

Sample Input

1100000

 

 

Sample Output

610

 

 

Source

ACM暑期集训队练习赛（六）

 

 

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数学题。先暴力打表吧

 

#include<cmath>#include<cstdlib>#include<algorithm>#include<string>#include<vector>#include<iostream>#include<map>using namespace std;int num[]={6,16,8,10,25,7,14,3,23,17,13,17,0,27,7,14,15,17,26,26,20,17,9,22,22,23,0,1};int main(){    int n;    while(scanf("%d",&n))    {        if(n==0) break;        printf("%d\n",num[(n-1)%28]);    }    return 0;}