hdoj1159 (dp 最长公共子序列)

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题目:http://acm.hdu.edu.cn/showproblem.php?pid=1159

Common Subsequence


Problem Description
A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <z1, z2, ..., zk> is a subsequence of X if there exists a strictly increasing sequence <i1, i2, ..., ik> of indices of X such that for all j = 1,2,...,k, xij = zj. For example, Z = <a, b, f, c> is a subsequence of X = <a, b, c, f, b, c> with index sequence <1, 2, 4, 6>. Given two sequences X and Y the problem is to find the length of the maximum-length common subsequence of X and Y. 
The program input is from a text file. Each data set in the file contains two strings representing the given sequences. The sequences are separated by any number of white spaces. The input data are correct. For each set of data the program prints on the standard output the length of the maximum-length common subsequence from the beginning of a separate line. 
 
Sample Input
abcfbc abfcabprogramming contest abcd mnp 

Sample Output
420
 
求最长公共子序列,
if(s1[i]==s2[j])dp[i][j]=dp[i-1][j-1]+1;else    dp[i][j]=max(dp[i][j-1],dp[i-1][j]);
这个题目有个地方没想清楚,自己的代码第一次把dp[][]初始化为0以后,之后就应该不必再初始化的,
但提交的时候不初始化就报错,找了很久没找到原因

#include<stdio.h>#include<string.h>#define N 500 int dp[N][N]={0};int max(int x,int y){    if(x>y)return x;    return y;}int main(){    int i,j,k;    char s1[N],s2[N];    while(scanf("%s%s",s1+1,s2+1)!=EOF)    {       memset(dp,0,sizeof(dp));        for(i=1;s1[i];i++)        {            for(j=1;s2[j];j++)            {                if(s1[i]==s2[j])dp[i][j]=dp[i-1][j-1]+1;                else                    dp[i][j]=max(dp[i][j-1],dp[i-1][j]);            }        }        printf("%d\n",dp[i-1][j-1]);    }    return 0;}


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