[BZOJ1088][SCOI2005]扫雷Mine
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题目:BZOJ1088
这道题其实是递推,确定了上一个格子是否有雷,即可确定当前第i个各自是否有雷。
所以一开始就判断第一个格子是否有雷。
附代码:
#include<cstdio>#include<cstring>using namespace std;int a[11000],f[11000];int n,ans;int main(){ scanf("%d",&n); for(int i=1;i<=n;i++)scanf("%d",&a[i]); memset(f,0,sizeof(f)); ans=0; for(int i=0;i<=a[1];i++) { memset(f,0,sizeof(f)); f[1]=i; f[2]=a[1]-i; for(int j=2;j<=n;j++)f[j+1]=a[j]-f[j]-f[j-1]; if(f[n+1]==0)ans++; } printf("%d\n",ans); return 0;}
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