HDU 6170

题目

Two strings

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 1214    Accepted Submission(s): 504

Problem Description

Giving two strings and you should judge if they are matched.
The first string contains lowercase letters and uppercase letters.
The second string contains lowercase letters, uppercase letters, and special symbols: “.” and “*”.
. can match any letter, and * means the front character can appear any times. For example, “a.b” can match “acb” or “abb”, “a*” can match “a”, “aa” and even empty string. ( “*” will not appear in the front of the string, and there will not be two consecutive “*”.

 

Input

The first line contains an integer T implying the number of test cases. (T≤15)
For each test case, there are two lines implying the two strings (The length of the two strings is less than 2500).

 

Output

For each test case, print “yes” if the two strings are matched, otherwise print “no”.

 

Sample Input

3aaa*abba.*abbaab

 

 传送门  ：http://blog.csdn.net/algzjh/article/details/77484741

正则表达式，orz ,真的厉害

#include<iostream>#include<cstdio>#include<algorithm>#include<cstring>#include<string>#include<regex>using namespace std;const int MAXN=2600;string s,p;int main(){    int T;    cin>>T;    while(T--)    {        cin>>s>>p;        string s1=".*";        string s2="(a*|b*|c*|d*|e*|f*|g*|h*|i*|j*|k*|l*|m*|n*|o*|p*|q*|r*|s*|t*|u*|v*|w*|x*|y*|z*"                "|A*|B*|C*|D*|E*|F*|G*|H*|I*|J*|K*|L*|M*|N*|O*|P*|Q*|R*|S*|T*|U*|V*|W*|X*|Y*|Z*)";///代表其中的一种有| 代表或        //string s2="(.)\\1*";        int len=s2.length();        auto pos=p.find(s1);        while(pos!=string::npos)        {            p.replace(pos,2,s2);            pos=p.find(s1,pos+len);        }        regex pat(p);///就这么用的我能有什么办法？        if(regex_match(s,pat)) cout<<"yes"<<endl;        else cout<<"no"<<endl;    }    return 0;}