POJ 1466 Girls and Boys(最大独立集)
来源:互联网 发布:c语言open函数 编辑:程序博客网 时间:2024/05/16 02:24
题目地址:点击打开链接
题意:
有n个学生,一些学生之间存在关系,现在要把学生弄到一个集合,这个集合中的学生两两不能有关系,求这个集合的
最大学生数是多少。
思路:
将每个点拆成两个点,一个当作是男的点,一个当作是女的点了,然后连边。由于关系是相互的,这样就造成了边的重
复。也就是边集是刚才的二倍,从而导致了最大匹配变成了
二倍。那么答案就是最大独立集=顶点数-最大匹配/2
代码:
#include<iostream>#include<cstdio>#include<cstring>#include<vector>using namespace std;const int maxn = 505;vector<int> g[maxn];int n, m, match[maxn];bool vis[maxn];bool dfs(int x){ for(int i = 0; i < g[x].size(); i++) { int v = g[x][i]; if(!vis[v]) { vis[v] = 1; if(match[v] == -1 || dfs(match[v])) { match[v] = x; return 1; } } } return 0;}int Hungary(){ int res = 0; for(int i = 1; i <= n; i++) { memset(vis, 0, sizeof(vis)); res += dfs(i); } return res;}int main(void){ while(cin >> n) { memset(match, -1, sizeof(match)); for(int i = 0; i < maxn; i++) g[i].clear(); for(int i = 1; i <= n; i++) { int t = 0; scanf("%d: (%d)", &t, &m); while(m--) { scanf("%d", &t); t++; g[i].push_back(t); g[t].push_back(i); } } printf("%d\n", n-Hungary()/2); } return 0;}
Girls and Boys
Time Limit: 5000MS Memory Limit: 10000KTotal Submissions: 12485 Accepted: 5578
Description
In the second year of the university somebody started a study on the romantic relations between the students. The relation "romantically involved" is defined between one girl and one boy. For the study reasons it is necessary to find out the maximum set satisfying the condition: there are no two students in the set who have been "romantically involved". The result of the program is the number of students in such a set.
Input
The input contains several data sets in text format. Each data set represents one set of subjects of the study, with the following description:
the number of students
the description of each student, in the following format
student_identifier:(number_of_romantic_relations) student_identifier1 student_identifier2 student_identifier3 ...
or
student_identifier:(0)
The student_identifier is an integer number between 0 and n-1 (n <=500 ), for n subjects.
the number of students
the description of each student, in the following format
student_identifier:(number_of_romantic_relations) student_identifier1 student_identifier2 student_identifier3 ...
or
student_identifier:(0)
The student_identifier is an integer number between 0 and n-1 (n <=500 ), for n subjects.
Output
For each given data set, the program should write to standard output a line containing the result.
Sample Input
70: (3) 4 5 61: (2) 4 62: (0)3: (0)4: (2) 0 15: (1) 06: (2) 0 130: (2) 1 21: (1) 02: (1) 0
Sample Output
52
Source
1 0
- POJ 1466 Girls and Boys (最大独立集Hungary)
- poj 1466 Girls and Boys (最大独立集)
- POJ 1466 Girls and Boys(最大独立点集)
- POJ 1466 Girls and Boys(最大独立集)
- poj 1466 Girls and Boys (最大独立)
- pku(poj) 1466 Girls and Boys (最大独立集)
- POJ 1466 Girls and Boys(最大独立点集)
- POJ 1466 Girls and Boys (最大独立点集)
- POJ 1466 Girls and Boys 最大独立集
- POJ-1466-Girls and Boys(二分图最大独立集)
- POJ 1466 Girls and Boys(二分图最大独立集)
- POJ 1466 Girls and Boys (匈牙利算法 最大独立集)
- poj 1466 && hdu 1068Girls and Boys(最大独立集)
- POJ 1466 Girls and Boys(二分图最大独立集)
- POJ 1466 Girls and Boys(二分图最大独立集)
- POJ-1466 Girls and Boys(最大独立集)
- POJ 1466 Girls and Boys(二分图最大独立集)
- poj 1466 Girls and Boys (二分图最大独立集)
- Dynamic Web project,Jsp可正常访问,servlet出现404,刷新出现Http500,解决方式
- 剑指offer_13(在O(1)的时间内删除链表中的某一个元素)
- Android的JNI【实战教程】1⃣️--java和c/c++的那些事
- namespace
- java读取ppt,java导出ppt
- POJ 1466 Girls and Boys(最大独立集)
- Swift开发:UIAlertController 弹框
- 使用SIFT描述子计算模板旋转角度
- Eclipse通过maven构建SpringMVC项目
- 验证是否符合手机号格式
- java se 08
- 矩阵乘法
- leaflet.js +highcharts 关键代码
- android 3DES加密解密